-2(2x-4)-3x-(-2-2)^2=-7^0-3(4x-1)-9-6x

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Solution for -2(2x-4)-3x-(-2-2)^2=-7^0-3(4x-1)-9-6x equation: 



-2(2x-4)-3x-(-2-2)^2=-7^0-3(4x-1)-9-6x

We move all terms to the left:

-2(2x-4)-3x-(-2-2)^2-(-7^0-3(4x-1)-9-6x)=0

We add all the numbers together, and all the variables

-2(2x-4)-3x-(-7^0-3(4x-1)-9-6x)-(-4)^2=0

We add all the numbers together, and all the variables

-3x-2(2x-4)-(-7^0-3(4x-1)-9-6x)-16=0

We multiply parentheses

-3x-4x-(-7^0-3(4x-1)-9-6x)+8-16=0



We calculate terms in parentheses: -(-7^0-3(4x-1)-9-6x), so:

-7^0-3(4x-1)-9-6x

determiningTheFunctionDomain
-3(4x-1)-6x-9-7^0

We add all the numbers together, and all the variables

-6x-3(4x-1)-10

We multiply parentheses

-6x-12x+3-10

We add all the numbers together, and all the variables

-18x-7

Back to the equation:

-(-18x-7)



We add all the numbers together, and all the variables

-7x-(-18x-7)-8=0

We get rid of parentheses

-7x+18x+7-8=0

We add all the numbers together, and all the variables

11x-1=0

We move all terms containing x to the left, all other terms to the right

11x=1

x=1/11

x=1/11

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